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BaseRepresentation
bin11000110011111
3122102111
43012133
5401303
6134451
752015
oct30637
918374
1012703
1195a9
127427
135a22
1448b5
153b6d
hex319f

12703 has 2 divisors, whose sum is σ = 12704. Its totient is φ = 12702.

The previous prime is 12697. The next prime is 12713. The reversal of 12703 is 30721.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12703 - 25 = 12671 is a prime.

It is a super-2 number, since 2×127032 = 322732418, which contains 22 as substring.

It is an alternating number because its digits alternate between odd and even.

It is a zygodrome in base 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6351 + 6352.

It is an arithmetic number, because the mean of its divisors is an integer number (6352).

12703 is a deficient number, since it is larger than the sum of its proper divisors (1).

12703 is an equidigital number, since it uses as much as digits as its factorization.

12703 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 42, while the sum is 13.

The square root of 12703 is about 112.7075862575. The cubic root of 12703 is about 23.3329024864.

It can be divided in two parts, 1 and 2703, that added together give a square (2704 = 522).

The spelling of 12703 in words is "twelve thousand, seven hundred three", and thus it is an iban number.