128492333 has 2 divisors, whose sum is σ = 128492334. Its totient is φ = 128492332.

The previous prime is 128492327. The next prime is 128492339. The reversal of 128492333 is 333294821.

It is a balanced prime because it is at equal distance from previous prime (128492327) and next prime (128492339).

It can be written as a sum of positive squares in only one way, i.e., 67683529 + 60808804 = 8227^2 + 7798^2 .

It is a cyclic number.

It is not a de Polignac number, because 128492333 - 2¹⁰ = 128491309 is a prime.

It is a super-3 number, since 3×128492333³ (a number of 25 digits) contains 333 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 128492293 and 128492302.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (128492339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64246166 + 64246167.

It is an arithmetic number, because the mean of its divisors is an integer number (64246167).

Almost surely, 2^128492333 is an apocalyptic number.

It is an amenable number.

128492333 is a deficient number, since it is larger than the sum of its proper divisors (1).

128492333 is an equidigital number, since it uses as much as digits as its factorization.

128492333 is an evil number, because the sum of its binary digits is even.

The product of its digits is 31104, while the sum is 35.

The square root of 128492333 is about 11335.4458668374. The cubic root of 128492333 is about 504.6137398612.

The spelling of 128492333 in words is "one hundred twenty-eight million, four hundred ninety-two thousand, three hundred thirty-three".