1300014113 has 4 divisors (see below), whose sum is σ = 1300892208. Its totient is φ = 1299136020.

The previous prime is 1300014097. The next prime is 1300014139. The reversal of 1300014113 is 3114100031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3114100031 = 7 ⋅444871433.

It is a cyclic number.

It is not a de Polignac number, because 1300014113 - 2⁴ = 1300014097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1300014013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 436823 + ... + 439788.

It is an arithmetic number, because the mean of its divisors is an integer number (325223052).

Almost surely, 2^1300014113 is an apocalyptic number.

It is an amenable number.

1300014113 is a deficient number, since it is larger than the sum of its proper divisors (878095).

1300014113 is an equidigital number, since it uses as much as digits as its factorization.

1300014113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 878094.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 1300014113 is about 36055.7084662055. The cubic root of 1300014113 is about 1091.3968324898.

Adding to 1300014113 its reverse (3114100031), we get a palindrome (4414114144).

The spelling of 1300014113 in words is "one billion, three hundred million, fourteen thousand, one hundred thirteen".