130002032411231 has 8 divisors (see below), whose sum is σ = 130753803543744. Its totient is φ = 129250264891680.

The previous prime is 130002032411191. The next prime is 130002032411309. The reversal of 130002032411231 is 132114230200031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130002032411231 - 2³⁸ = 129727154504287 is a prime.

It is a super-2 number, since 2×130002032411231² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130002032411197 and 130002032411206.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130002037411231) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 111822746 + ... + 112979336.

It is an arithmetic number, because the mean of its divisors is an integer number (16344225442968).

Almost surely, 2^{130002032411231} is an apocalyptic number.

130002032411231 is a deficient number, since it is larger than the sum of its proper divisors (751771132513).

130002032411231 is a wasteful number, since it uses less digits than its factorization.

130002032411231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1806481.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 130002032411231 its reverse (132114230200031), we get a palindrome (262116262611262).

The spelling of 130002032411231 in words is "one hundred thirty trillion, two billion, thirty-two million, four hundred eleven thousand, two hundred thirty-one".