Base | Representation |
---|---|
bin | 11101100011110011000000… |
… | …101001100000100111110010 |
3 | 122001022012020122201120012021 |
4 | 131203303000221200213302 |
5 | 114014433230332103242 |
6 | 1140254405332022054 |
7 | 36245300010141004 |
oct | 3543630051404762 |
9 | 561265218646167 |
10 | 130003302222322 |
11 | 384720aaa1a791 |
12 | 126b7616a6192a |
13 | 5770349764ba9 |
14 | 241629c996374 |
15 | 1006a3e439b67 |
hex | 763cc0a609f2 |
130003302222322 has 4 divisors (see below), whose sum is σ = 195004953333486. Its totient is φ = 65001651111160.
The previous prime is 130003302222281. The next prime is 130003302222329. The reversal of 130003302222322 is 223222203300031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 125202247163161 + 4801055059161 = 11189381^2 + 2191131^2 .
It is not an unprimeable number, because it can be changed into a prime (130003302222329) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32500825555579 + ... + 32500825555582.
Almost surely, 2130003302222322 is an apocalyptic number.
130003302222322 is a deficient number, since it is larger than the sum of its proper divisors (65001651111164).
130003302222322 is an equidigital number, since it uses as much as digits as its factorization.
130003302222322 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65001651111163.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 130003302222322 its reverse (223222203300031), we get a palindrome (353225505522353).
The spelling of 130003302222322 in words is "one hundred thirty trillion, three billion, three hundred two million, two hundred twenty-two thousand, three hundred twenty-two".
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