Base | Representation |
---|---|
bin | 1011110100110000100000… |
… | …0011110001010110100101 |
3 | 1201000212212010110022222112 |
4 | 2331030020003301112211 |
5 | 3201002022302230201 |
6 | 43352324424010405 |
7 | 2511201633635645 |
oct | 275141003612645 |
9 | 51025763408875 |
10 | 13001001211301 |
11 | 416276a280654 |
12 | 155b821000a05 |
13 | 733cb222aa3c |
14 | 32d374daa525 |
15 | 1782bc5070bb |
hex | bd3080f15a5 |
13001001211301 has 2 divisors, whose sum is σ = 13001001211302. Its totient is φ = 13001001211300.
The previous prime is 13001001211241. The next prime is 13001001211337. The reversal of 13001001211301 is 10311210010031.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12963384220900 + 37616990401 = 3600470^2 + 193951^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13001001211301 is a prime.
It is a super-2 number, since 2×130010012113012 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13001001211351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500500605650 + 6500500605651.
It is an arithmetic number, because the mean of its divisors is an integer number (6500500605651).
Almost surely, 213001001211301 is an apocalyptic number.
It is an amenable number.
13001001211301 is a deficient number, since it is larger than the sum of its proper divisors (1).
13001001211301 is an equidigital number, since it uses as much as digits as its factorization.
13001001211301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 14.
Adding to 13001001211301 its reverse (10311210010031), we get a palindrome (23312211221332).
The spelling of 13001001211301 in words is "thirteen trillion, one billion, one million, two hundred eleven thousand, three hundred one".
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