13001001211321 has 4 divisors (see below), whose sum is σ = 13001714668672. Its totient is φ = 13000287753972.

The previous prime is 13001001211301. The next prime is 13001001211337. The reversal of 13001001211321 is 12311210010031.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13001001211321 - 2¹⁹ = 13001000687033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13001001211295 and 13001001211304.

It is not an unprimeable number, because it can be changed into a prime (13001001211301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 356701341 + ... + 356737786.

It is an arithmetic number, because the mean of its divisors is an integer number (3250428667168).

Almost surely, 2^{13001001211321} is an apocalyptic number.

It is an amenable number.

13001001211321 is a deficient number, since it is larger than the sum of its proper divisors (713457351).

13001001211321 is an equidigital number, since it uses as much as digits as its factorization.

13001001211321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 713457350.

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 13001001211321 its reverse (12311210010031), we get a palindrome (25312211221352).

The spelling of 13001001211321 in words is "thirteen trillion, one billion, one million, two hundred eleven thousand, three hundred twenty-one".