Base | Representation |
---|---|
bin | 1011110100110000100000… |
… | …0011110001100011100011 |
3 | 1201000212212010110101010021 |
4 | 2331030020003301203203 |
5 | 3201002022302242011 |
6 | 43352324424014311 |
7 | 2511201633641242 |
oct | 275141003614343 |
9 | 51025763411107 |
10 | 13001001212131 |
11 | 416276a281239 |
12 | 155b821001397 |
13 | 733cb222b22a |
14 | 32d374daa959 |
15 | 1782bc507471 |
hex | bd3080f18e3 |
13001001212131 has 2 divisors, whose sum is σ = 13001001212132. Its totient is φ = 13001001212130.
The previous prime is 13001001212123. The next prime is 13001001212153. The reversal of 13001001212131 is 13121210010031.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13001001212131 - 23 = 13001001212123 is a prime.
It is a super-2 number, since 2×130010012121312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13001001218131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500500606065 + 6500500606066.
It is an arithmetic number, because the mean of its divisors is an integer number (6500500606066).
Almost surely, 213001001212131 is an apocalyptic number.
13001001212131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13001001212131 is an equidigital number, since it uses as much as digits as its factorization.
13001001212131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 16.
Adding to 13001001212131 its reverse (13121210010031), we get a palindrome (26122211222162).
The spelling of 13001001212131 in words is "thirteen trillion, one billion, one million, two hundred twelve thousand, one hundred thirty-one".
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