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BaseRepresentation
bin1011110100110000100000…
…0011110001100011100011
31201000212212010110101010021
42331030020003301203203
53201002022302242011
643352324424014311
72511201633641242
oct275141003614343
951025763411107
1013001001212131
11416276a281239
12155b821001397
13733cb222b22a
1432d374daa959
151782bc507471
hexbd3080f18e3

13001001212131 has 2 divisors, whose sum is σ = 13001001212132. Its totient is φ = 13001001212130.

The previous prime is 13001001212123. The next prime is 13001001212153. The reversal of 13001001212131 is 13121210010031.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13001001212131 - 23 = 13001001212123 is a prime.

It is a super-2 number, since 2×130010012121312 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13001001218131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500500606065 + 6500500606066.

It is an arithmetic number, because the mean of its divisors is an integer number (6500500606066).

Almost surely, 213001001212131 is an apocalyptic number.

13001001212131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13001001212131 is an equidigital number, since it uses as much as digits as its factorization.

13001001212131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 13001001212131 its reverse (13121210010031), we get a palindrome (26122211222162).

The spelling of 13001001212131 in words is "thirteen trillion, one billion, one million, two hundred twelve thousand, one hundred thirty-one".