13001110099 has 2 divisors, whose sum is σ = 13001110100. Its totient is φ = 13001110098.

The previous prime is 13001110097. The next prime is 13001110159. The reversal of 13001110099 is 99001110031.

13001110099 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13001110099 - 2¹ = 13001110097 is a prime.

Together with 13001110097, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13001110091) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500555049 + 6500555050.

It is an arithmetic number, because the mean of its divisors is an integer number (6500555050).

Almost surely, 2^13001110099 is an apocalyptic number.

13001110099 is a deficient number, since it is larger than the sum of its proper divisors (1).

13001110099 is an equidigital number, since it uses as much as digits as its factorization.

13001110099 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243, while the sum is 25.

The spelling of 13001110099 in words is "thirteen billion, one million, one hundred ten thousand, ninety-nine".