Base | Representation |
---|---|
bin | 11101100100000001000101… |
… | …010110011110011000000000 |
3 | 122001100122020210021012122110 |
4 | 131210001011112132120000 |
5 | 114020210202324112000 |
6 | 1140305345023135320 |
7 | 36246343331000550 |
oct | 3544010526363000 |
9 | 561318223235573 |
10 | 130018413504000 |
11 | 3847855493932a |
12 | 126ba533744540 |
13 | 57718b7374798 |
14 | 2416cd38a7160 |
15 | 1007125dd1850 |
hex | 76404559e600 |
130018413504000 has 320 divisors, whose sum is σ = 494032828303872. Its totient is φ = 29718494208000.
The previous prime is 130018413503981. The next prime is 130018413504017. The reversal of 130018413504000 is 405314810031.
130018413504000 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a tau number, because it is divible by the number of its divisors (320).
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 47025946 + ... + 49713945.
Almost surely, 2130018413504000 is an apocalyptic number.
130018413504000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130018413504000 is an abundant number, since it is smaller than the sum of its proper divisors (364014414799872).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130018413504000 is an frugal number, since it uses more digits than its factorization.
130018413504000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 96739934 (or 96739908 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 30.
The spelling of 130018413504000 in words is "one hundred thirty trillion, eighteen billion, four hundred thirteen million, five hundred four thousand".
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