Search a number
-
+
130022141241 = 343340713747
BaseRepresentation
bin111100100010111101…
…1000110110100111001
3110102121110121010200210
41321011323012310321
54112241132004431
6135421545421333
712252032652036
oct1710573066471
9412543533623
10130022141241
1150162122183
122124819a849
13c351657765
1464163d038d
1535aec88d46
hex1e45ec6d39

130022141241 has 4 divisors (see below), whose sum is σ = 173362854992. Its totient is φ = 86681427492.

The previous prime is 130022141213. The next prime is 130022141323. The reversal of 130022141241 is 142141220031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 130022141241 - 26 = 130022141177 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130022141341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21670356871 + ... + 21670356876.

It is an arithmetic number, because the mean of its divisors is an integer number (43340713748).

Almost surely, 2130022141241 is an apocalyptic number.

It is an amenable number.

130022141241 is a deficient number, since it is larger than the sum of its proper divisors (43340713751).

130022141241 is an equidigital number, since it uses as much as digits as its factorization.

130022141241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43340713750.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 130022141241 its reverse (142141220031), we get a palindrome (272163361272).

The spelling of 130022141241 in words is "one hundred thirty billion, twenty-two million, one hundred forty-one thousand, two hundred forty-one".

Divisors: 1 3 43340713747 130022141241