Base | Representation |
---|---|
bin | 111100100011000100… |
… | …0000111011011000011 |
3 | 110102121201000101202201 |
4 | 1321012020013123003 |
5 | 4112243020122210 |
6 | 135422150454031 |
7 | 12252103644454 |
oct | 1710610073303 |
9 | 412551011681 |
10 | 130025551555 |
11 | 50164041419 |
12 | 21249364317 |
13 | c35227cab3 |
14 | 6416a3b12b |
15 | 35b020e53a |
hex | 1e462076c3 |
130025551555 has 4 divisors (see below), whose sum is σ = 156030661872. Its totient is φ = 104020441240.
The previous prime is 130025551549. The next prime is 130025551571. The reversal of 130025551555 is 555155520031.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 130025551555 - 215 = 130025518787 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13002555151 + ... + 13002555160.
It is an arithmetic number, because the mean of its divisors is an integer number (39007665468).
Almost surely, 2130025551555 is an apocalyptic number.
130025551555 is a deficient number, since it is larger than the sum of its proper divisors (26005110317).
130025551555 is an equidigital number, since it uses as much as digits as its factorization.
130025551555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26005110316.
The product of its (nonzero) digits is 93750, while the sum is 37.
The spelling of 130025551555 in words is "one hundred thirty billion, twenty-five million, five hundred fifty-one thousand, five hundred fifty-five".
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