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130025551555 = 526005110311
BaseRepresentation
bin111100100011000100…
…0000111011011000011
3110102121201000101202201
41321012020013123003
54112243020122210
6135422150454031
712252103644454
oct1710610073303
9412551011681
10130025551555
1150164041419
1221249364317
13c35227cab3
146416a3b12b
1535b020e53a
hex1e462076c3

130025551555 has 4 divisors (see below), whose sum is σ = 156030661872. Its totient is φ = 104020441240.

The previous prime is 130025551549. The next prime is 130025551571. The reversal of 130025551555 is 555155520031.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 130025551555 - 215 = 130025518787 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13002555151 + ... + 13002555160.

It is an arithmetic number, because the mean of its divisors is an integer number (39007665468).

Almost surely, 2130025551555 is an apocalyptic number.

130025551555 is a deficient number, since it is larger than the sum of its proper divisors (26005110317).

130025551555 is an equidigital number, since it uses as much as digits as its factorization.

130025551555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26005110316.

The product of its (nonzero) digits is 93750, while the sum is 37.

The spelling of 130025551555 in words is "one hundred thirty billion, twenty-five million, five hundred fifty-one thousand, five hundred fifty-five".

Divisors: 1 5 26005110311 130025551555