Base | Representation |
---|---|
bin | 111100100011100000… |
… | …0110101011100000110 |
3 | 110102122201222210120122 |
4 | 1321013000311130012 |
5 | 4112310321420402 |
6 | 135423441301542 |
7 | 12252344222135 |
oct | 1710700653406 |
9 | 412581883518 |
10 | 130040420102 |
11 | 5017147737a |
12 | 212523348b2 |
13 | c355387658 |
14 | 64189cb91c |
15 | 35b1699ca2 |
hex | 1e47035706 |
130040420102 has 4 divisors (see below), whose sum is σ = 195060630156. Its totient is φ = 65020210050.
The previous prime is 130040420099. The next prime is 130040420171. The reversal of 130040420102 is 201024040031.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32510105024 + ... + 32510105027.
It is an arithmetic number, because the mean of its divisors is an integer number (48765157539).
Almost surely, 2130040420102 is an apocalyptic number.
130040420102 is a deficient number, since it is larger than the sum of its proper divisors (65020210054).
130040420102 is an equidigital number, since it uses as much as digits as its factorization.
130040420102 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65020210053.
The product of its (nonzero) digits is 192, while the sum is 17.
Adding to 130040420102 its reverse (201024040031), we get a palindrome (331064460133).
The spelling of 130040420102 in words is "one hundred thirty billion, forty million, four hundred twenty thousand, one hundred two".
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