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13004341441 = 713142904851
BaseRepresentation
bin11000001110001111…
…01000000011000001
31020120021221222210121
430013013220003001
5203113102411231
65550224100241
7640155035620
oct140707500301
936507858717
1013004341441
115573680223
12262b164681
1312c3261ac0
148b51796b7
15511a0d311
hex3071e80c1

13004341441 has 8 divisors (see below), whose sum is σ = 16005343424. Its totient is φ = 10289149200.

The previous prime is 13004341433. The next prime is 13004341457. The reversal of 13004341441 is 14414340031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13004341441 - 23 = 13004341433 is a prime.

It is a super-2 number, since 2×130043414412 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13004341411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 71452335 + ... + 71452516.

It is an arithmetic number, because the mean of its divisors is an integer number (2000667928).

Almost surely, 213004341441 is an apocalyptic number.

It is an amenable number.

13004341441 is a deficient number, since it is larger than the sum of its proper divisors (3001001983).

13004341441 is a wasteful number, since it uses less digits than its factorization.

13004341441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 142904871.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 13004341441 its reverse (14414340031), we get a palindrome (27418681472).

The spelling of 13004341441 in words is "thirteen billion, four million, three hundred forty-one thousand, four hundred forty-one".

Divisors: 1 7 13 91 142904851 1000333957 1857763063 13004341441