Base | Representation |
---|---|
bin | 110001100111… |
… | …001110000111 |
3 | 220110202110201 |
4 | 301213032013 |
5 | 11312140303 |
6 | 1142431331 |
7 | 215355334 |
oct | 61471607 |
9 | 26422421 |
10 | 13005703 |
11 | 7383417 |
12 | 4432547 |
13 | 29049a9 |
14 | 1a2798b |
15 | 121d81d |
hex | c67387 |
13005703 has 2 divisors, whose sum is σ = 13005704. Its totient is φ = 13005702.
The previous prime is 13005701. The next prime is 13005719. The reversal of 13005703 is 30750031.
13005703 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13005703 - 21 = 13005701 is a prime.
It is a super-4 number, since 4×130057034 (a number of 30 digits) contains 4444 as substring.
Together with 13005701, it forms a pair of twin primes.
It is a zygodrome in base 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13005701) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502851 + 6502852.
It is an arithmetic number, because the mean of its divisors is an integer number (6502852).
Almost surely, 213005703 is an apocalyptic number.
13005703 is a deficient number, since it is larger than the sum of its proper divisors (1).
13005703 is an equidigital number, since it uses as much as digits as its factorization.
13005703 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 315, while the sum is 19.
The square root of 13005703 is about 3606.3420525513. The cubic root of 13005703 is about 235.1678474933.
Adding to 13005703 its reverse (30750031), we get a palindrome (43755734).
The spelling of 13005703 in words is "thirteen million, five thousand, seven hundred three".
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