Base | Representation |
---|---|
bin | 1011110101010011100110… |
… | …0110110110000111000001 |
3 | 1201001210011201010112012020 |
4 | 2331110321212312013001 |
5 | 3201130321120032001 |
6 | 43400523333152053 |
7 | 2511654252631242 |
oct | 275247146660701 |
9 | 51053151115166 |
10 | 13010422424001 |
11 | 4166764306152 |
12 | 156161018b629 |
13 | 734b54038a02 |
14 | 32d9ca308cc9 |
15 | 17866e687736 |
hex | bd5399b61c1 |
13010422424001 has 8 divisors (see below), whose sum is σ = 17716319896704. Its totient is φ = 8489069950320.
The previous prime is 13010422423969. The next prime is 13010422424003. The reversal of 13010422424001 is 10042422401031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13010422424001 - 25 = 13010422423969 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (13010422424003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 46136249590 + ... + 46136249871.
It is an arithmetic number, because the mean of its divisors is an integer number (2214539987088).
Almost surely, 213010422424001 is an apocalyptic number.
It is an amenable number.
13010422424001 is a deficient number, since it is larger than the sum of its proper divisors (4705897472703).
13010422424001 is an equidigital number, since it uses as much as digits as its factorization.
13010422424001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 92272499511.
The product of its (nonzero) digits is 1536, while the sum is 24.
Adding to 13010422424001 its reverse (10042422401031), we get a palindrome (23052844825032).
The spelling of 13010422424001 in words is "thirteen trillion, ten billion, four hundred twenty-two million, four hundred twenty-four thousand, one".
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