Base | Representation |
---|---|
bin | 11000001111010001… |
… | …10011110110010011 |
3 | 1020120220022221201010 |
4 | 30013220303312103 |
5 | 203122314244111 |
6 | 5551134342003 |
7 | 640322006451 |
oct | 140750636623 |
9 | 36526287633 |
10 | 13013040531 |
11 | 5578581a57 |
12 | 263205a903 |
13 | 12c4cb94aa |
14 | 8b63a19d1 |
15 | 51267aaa6 |
hex | 307a33d93 |
13013040531 has 32 divisors (see below), whose sum is σ = 18471075840. Its totient is φ = 8136727200.
The previous prime is 13013040479. The next prime is 13013040539. The reversal of 13013040531 is 13504031031.
It is not a de Polignac number, because 13013040531 - 211 = 13013038483 is a prime.
It is a super-3 number, since 3×130130405313 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 13013040498 and 13013040507.
It is not an unprimeable number, because it can be changed into a prime (13013040539) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 372876 + ... + 406278.
It is an arithmetic number, because the mean of its divisors is an integer number (577221120).
Almost surely, 213013040531 is an apocalyptic number.
13013040531 is a deficient number, since it is larger than the sum of its proper divisors (5458035309).
13013040531 is a wasteful number, since it uses less digits than its factorization.
13013040531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33567.
The product of its (nonzero) digits is 540, while the sum is 21.
Adding to 13013040531 its reverse (13504031031), we get a palindrome (26517071562).
The spelling of 13013040531 in words is "thirteen billion, thirteen million, forty thousand, five hundred thirty-one".
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