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13022100213233 is a prime number
BaseRepresentation
bin1011110101111111000110…
…1010000100110111110001
31201002220022112221200110112
42331133301222010313301
53201323230123310413
643410134212511105
72512546532331056
oct275376152046761
951086275850415
1013022100213233
1141707070a3031
12156392b01b495
13735c954c6c77
143303b721102d
15178b049ad2a8
hexbd7f1a84df1

13022100213233 has 2 divisors, whose sum is σ = 13022100213234. Its totient is φ = 13022100213232.

The previous prime is 13022100213211. The next prime is 13022100213253. The reversal of 13022100213233 is 33231200122031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12897665534224 + 124434679009 = 3591332^2 + 352753^2 .

It is an emirp because it is prime and its reverse (33231200122031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13022100213233 - 222 = 13022096018929 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13022100213199 and 13022100213208.

It is not a weakly prime, because it can be changed into another prime (13022100213253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511050106616 + 6511050106617.

It is an arithmetic number, because the mean of its divisors is an integer number (6511050106617).

Almost surely, 213022100213233 is an apocalyptic number.

It is an amenable number.

13022100213233 is a deficient number, since it is larger than the sum of its proper divisors (1).

13022100213233 is an equidigital number, since it uses as much as digits as its factorization.

13022100213233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 13022100213233 its reverse (33231200122031), we get a palindrome (46253300335264).

The spelling of 13022100213233 in words is "thirteen trillion, twenty-two billion, one hundred million, two hundred thirteen thousand, two hundred thirty-three".