Base | Representation |
---|---|
bin | 1011110110000011010110… |
… | …1011101111100000000111 |
3 | 1201010000021002111002111221 |
4 | 2331200311223233200013 |
5 | 3201333044311010204 |
6 | 43410443342341211 |
7 | 2512620031163524 |
oct | 275406553574007 |
9 | 51100232432457 |
10 | 13023241500679 |
11 | 41711423481a3 |
12 | 1563ba928a807 |
13 | 736117aa2497 |
14 | 330484a1a14b |
15 | 178b6ec9c654 |
hex | bd835aef807 |
13023241500679 has 2 divisors, whose sum is σ = 13023241500680. Its totient is φ = 13023241500678.
The previous prime is 13023241500653. The next prime is 13023241500691. The reversal of 13023241500679 is 97600514232031.
It is a strong prime.
It is an emirp because it is prime and its reverse (97600514232031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13023241500679 - 239 = 12473485686791 is a prime.
It is a super-2 number, since 2×130232415006792 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13023241501679) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511620750339 + 6511620750340.
It is an arithmetic number, because the mean of its divisors is an integer number (6511620750340).
Almost surely, 213023241500679 is an apocalyptic number.
13023241500679 is a deficient number, since it is larger than the sum of its proper divisors (1).
13023241500679 is an equidigital number, since it uses as much as digits as its factorization.
13023241500679 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 272160, while the sum is 43.
The spelling of 13023241500679 in words is "thirteen trillion, twenty-three billion, two hundred forty-one million, five hundred thousand, six hundred seventy-nine".
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