Base | Representation |
---|---|
bin | 111100101010011010… |
… | …1011100010100100001 |
3 | 110110020220100021002212 |
4 | 1321110311130110201 |
5 | 4113244203032112 |
6 | 135502443451505 |
7 | 12261161255432 |
oct | 1712465342441 |
9 | 413226307085 |
10 | 130272314657 |
11 | 50280364171 |
12 | 212b7b26b95 |
13 | c39142b074 |
14 | 643b713489 |
15 | 35c6c04522 |
hex | 1e54d5c521 |
130272314657 has 2 divisors, whose sum is σ = 130272314658. Its totient is φ = 130272314656.
The previous prime is 130272314561. The next prime is 130272314701. The reversal of 130272314657 is 756413272031.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 105630850081 + 24641464576 = 325009^2 + 156976^2 .
It is a cyclic number.
It is not a de Polignac number, because 130272314657 - 218 = 130272052513 is a prime.
It is not a weakly prime, because it can be changed into another prime (130272314857) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65136157328 + 65136157329.
It is an arithmetic number, because the mean of its divisors is an integer number (65136157329).
Almost surely, 2130272314657 is an apocalyptic number.
It is an amenable number.
130272314657 is a deficient number, since it is larger than the sum of its proper divisors (1).
130272314657 is an equidigital number, since it uses as much as digits as its factorization.
130272314657 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 211680, while the sum is 41.
Adding to 130272314657 its reverse (756413272031), we get a palindrome (886685586688).
The spelling of 130272314657 in words is "one hundred thirty billion, two hundred seventy-two million, three hundred fourteen thousand, six hundred fifty-seven".
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