Base | Representation |
---|---|
bin | 1011110110011100111010… |
… | …0011110011010001010111 |
3 | 1201010122222011102000112222 |
4 | 2331213032203303101113 |
5 | 3201441121413102221 |
6 | 43413540151532555 |
7 | 2513252025416414 |
oct | 275471643632127 |
9 | 51118864360488 |
10 | 13030101300311 |
11 | 4174042543197 |
12 | 15653a268a15b |
13 | 73696c02ab14 |
14 | 330935abd10b |
15 | 178e221209ab |
hex | bd9ce8f3457 |
13030101300311 has 2 divisors, whose sum is σ = 13030101300312. Its totient is φ = 13030101300310.
The previous prime is 13030101300287. The next prime is 13030101300329. The reversal of 13030101300311 is 11300310103031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13030101300311 - 210 = 13030101299287 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13030101300311.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13030101300361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6515050650155 + 6515050650156.
It is an arithmetic number, because the mean of its divisors is an integer number (6515050650156).
Almost surely, 213030101300311 is an apocalyptic number.
13030101300311 is a deficient number, since it is larger than the sum of its proper divisors (1).
13030101300311 is an equidigital number, since it uses as much as digits as its factorization.
13030101300311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 13030101300311 its reverse (11300310103031), we get a palindrome (24330411403342).
The spelling of 13030101300311 in words is "thirteen trillion, thirty billion, one hundred one million, three hundred thousand, three hundred eleven".
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