Base | Representation |
---|---|
bin | 11101101000011010000101… |
… | …001111100011001110111000 |
3 | 122002102111001010222212110211 |
4 | 131220122011033203032320 |
5 | 114040131113041011212 |
6 | 1141100124230120504 |
7 | 36310214246414353 |
oct | 3550320517431670 |
9 | 562374033885424 |
10 | 130320133141432 |
11 | 385845047a0693 |
12 | 12748ab8ab0134 |
13 | 579419c537020 |
14 | 242775716329a |
15 | 100edd45229a7 |
hex | 7686853e33b8 |
130320133141432 has 32 divisors (see below), whose sum is σ = 263152690501680. Its totient is φ = 60146321114880.
The previous prime is 130320133141391. The next prime is 130320133141439. The reversal of 130320133141432 is 234141331023031.
It is a junction number, because it is equal to n+sod(n) for n = 130320133141394 and 130320133141403.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130320133141439) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10529869 + ... + 19274812.
Almost surely, 2130320133141432 is an apocalyptic number.
It is an amenable number.
130320133141432 is an abundant number, since it is smaller than the sum of its proper divisors (132832557360248).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130320133141432 is a wasteful number, since it uses less digits than its factorization.
130320133141432 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29846743 (or 29846739 counting only the distinct ones).
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 130320133141432 its reverse (234141331023031), we get a palindrome (364461464164463).
The spelling of 130320133141432 in words is "one hundred thirty trillion, three hundred twenty billion, one hundred thirty-three million, one hundred forty-one thousand, four hundred thirty-two".
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