Base | Representation |
---|---|
bin | 1111100010010… |
… | …01010110000011 |
3 | 100002020010201000 |
4 | 13301021112003 |
5 | 231330330333 |
6 | 20533143043 |
7 | 3141506616 |
oct | 761112603 |
9 | 302203630 |
10 | 130323843 |
11 | 67623261 |
12 | 3778aa83 |
13 | 21000000 |
14 | 1344617d |
15 | b694713 |
hex | 7c49583 |
130323843 has 28 divisors (see below), whose sum is σ = 209161720. Its totient is φ = 80199288.
The previous prime is 130323839. The next prime is 130323847. The reversal of 130323843 is 348323031.
The cubic root of 130323843 is 507.
It is a perfect power (a cube), and thus also a powerful number.
It is an interprime number because it is at equal distance from previous prime (130323839) and next prime (130323847).
It is not a de Polignac number, because 130323843 - 22 = 130323839 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a Duffinian number.
It is a nialpdrome in base 13.
It is not an unprimeable number, because it can be changed into a prime (130323847) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 10024905 + ... + 10024917.
Almost surely, 2130323843 is an apocalyptic number.
130323843 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
130323843 is a deficient number, since it is larger than the sum of its proper divisors (78837877).
130323843 is an frugal number, since it uses more digits than its factorization.
130323843 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 87 (or 16 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 27.
The square root of 130323843 is about 11415.9468726865.
Multiplying 130323843 by its sum of digits (27), we get a 6-th power (3518743761 = 396).
130323843 divided by its sum of digits (27) gives a 6-th power (4826809 = 136).
Adding to 130323843 its reverse (348323031), we get a palindrome (478646874).
The spelling of 130323843 in words is "one hundred thirty million, three hundred twenty-three thousand, eight hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •