Base | Representation |
---|---|
bin | 111100101110110101… |
… | …0011001010001011111 |
3 | 110110122020000110120111 |
4 | 1321131222121101133 |
5 | 4114100111213120 |
6 | 135525254030451 |
7 | 12264640136536 |
oct | 1713552312137 |
9 | 413566013514 |
10 | 130420413535 |
11 | 50346a18035 |
12 | 21339648427 |
13 | c3b6012839 |
14 | 645326531d |
15 | 35d4c0a75a |
hex | 1e5da9945f |
130420413535 has 8 divisors (see below), whose sum is σ = 156507515136. Its totient is φ = 104334318240.
The previous prime is 130420413499. The next prime is 130420413583. The reversal of 130420413535 is 535314024031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 130420413535 - 27 = 130420413407 is a prime.
It is a super-2 number, since 2×1304204135352 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 130420413497 and 130420413506.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 71205 + ... + 515665.
It is an arithmetic number, because the mean of its divisors is an integer number (19563439392).
Almost surely, 2130420413535 is an apocalyptic number.
130420413535 is a deficient number, since it is larger than the sum of its proper divisors (26087101601).
130420413535 is an equidigital number, since it uses as much as digits as its factorization.
130420413535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 503153.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 130420413535 its reverse (535314024031), we get a palindrome (665734437566).
The spelling of 130420413535 in words is "one hundred thirty billion, four hundred twenty million, four hundred thirteen thousand, five hundred thirty-five".
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