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130420413535 = 558687444461
BaseRepresentation
bin111100101110110101…
…0011001010001011111
3110110122020000110120111
41321131222121101133
54114100111213120
6135525254030451
712264640136536
oct1713552312137
9413566013514
10130420413535
1150346a18035
1221339648427
13c3b6012839
14645326531d
1535d4c0a75a
hex1e5da9945f

130420413535 has 8 divisors (see below), whose sum is σ = 156507515136. Its totient is φ = 104334318240.

The previous prime is 130420413499. The next prime is 130420413583. The reversal of 130420413535 is 535314024031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 130420413535 - 27 = 130420413407 is a prime.

It is a super-2 number, since 2×1304204135352 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130420413497 and 130420413506.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 71205 + ... + 515665.

It is an arithmetic number, because the mean of its divisors is an integer number (19563439392).

Almost surely, 2130420413535 is an apocalyptic number.

130420413535 is a deficient number, since it is larger than the sum of its proper divisors (26087101601).

130420413535 is an equidigital number, since it uses as much as digits as its factorization.

130420413535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 503153.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 130420413535 its reverse (535314024031), we get a palindrome (665734437566).

The spelling of 130420413535 in words is "one hundred thirty billion, four hundred twenty million, four hundred thirteen thousand, five hundred thirty-five".

Divisors: 1 5 58687 293435 444461 2222305 26084082707 130420413535