Base | Representation |
---|---|
bin | 1011110111001101001001… |
… | …1110111011100110010111 |
3 | 1201011220101201111110222010 |
4 | 2331303102132323212113 |
5 | 3202144132310100310 |
6 | 43423521223035303 |
7 | 2514220663015002 |
oct | 275632236734627 |
9 | 51156351443863 |
10 | 13043052034455 |
11 | 4179588929463 |
12 | 15679b789bb33 |
13 | 737c54140611 |
14 | 331403aa2539 |
15 | 17942e090320 |
hex | bdcd27bb997 |
13043052034455 has 64 divisors (see below), whose sum is σ = 21425576675328. Its totient is φ = 6773135016960.
The previous prime is 13043052034399. The next prime is 13043052034469. The reversal of 13043052034455 is 55443025034031.
It is not a de Polignac number, because 13043052034455 - 29 = 13043052033943 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 129869739 + ... + 129970131.
It is an arithmetic number, because the mean of its divisors is an integer number (334774635552).
Almost surely, 213043052034455 is an apocalyptic number.
13043052034455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13043052034455 is a deficient number, since it is larger than the sum of its proper divisors (8382524640873).
13043052034455 is a wasteful number, since it uses less digits than its factorization.
13043052034455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 101896.
The product of its (nonzero) digits is 432000, while the sum is 39.
Adding to 13043052034455 its reverse (55443025034031), we get a palindrome (68486077068486).
The spelling of 13043052034455 in words is "thirteen trillion, forty-three billion, fifty-two million, thirty-four thousand, four hundred fifty-five".
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