Base | Representation |
---|---|
bin | 10010111110110100011… |
… | …011010100001001101101 |
3 | 11121200220000202211202122 |
4 | 102332310123110021231 |
5 | 132332403422244442 |
6 | 2435122321002325 |
7 | 163145205223052 |
oct | 22766433241155 |
9 | 4550800684678 |
10 | 1304402149997 |
11 | 46321500a691 |
12 | 1909757833a5 |
13 | 9600a130c1b |
14 | 471c20a3029 |
15 | 23de5635dd2 |
hex | 12fb46d426d |
1304402149997 has 2 divisors, whose sum is σ = 1304402149998. Its totient is φ = 1304402149996.
The previous prime is 1304402149987. The next prime is 1304402150071. The reversal of 1304402149997 is 7999412044031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1302168547876 + 2233602121 = 1141126^2 + 47261^2 .
It is an emirp because it is prime and its reverse (7999412044031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1304402149997 - 214 = 1304402133613 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1304402149987) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652201074998 + 652201074999.
It is an arithmetic number, because the mean of its divisors is an integer number (652201074999).
Almost surely, 21304402149997 is an apocalyptic number.
It is an amenable number.
1304402149997 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304402149997 is an equidigital number, since it uses as much as digits as its factorization.
1304402149997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1959552, while the sum is 53.
The spelling of 1304402149997 in words is "one trillion, three hundred four billion, four hundred two million, one hundred forty-nine thousand, nine hundred ninety-seven".
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