13044240331431 has 8 divisors (see below), whose sum is σ = 17992055629680. Its totient is φ = 8396292627072.

The previous prime is 13044240331417. The next prime is 13044240331483. The reversal of 13044240331431 is 13413304244031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13044240331431 - 2⁵ = 13044240331399 is a prime.

It is a super-2 number, since 2×13044240331431² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13044240331392 and 13044240331401.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13044240331831) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 74966898370 + ... + 74966898543.

It is an arithmetic number, because the mean of its divisors is an integer number (2249006953710).

Almost surely, 2^{13044240331431} is an apocalyptic number.

13044240331431 is a deficient number, since it is larger than the sum of its proper divisors (4947815298249).

13044240331431 is a wasteful number, since it uses less digits than its factorization.

13044240331431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 149933796945.

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 13044240331431 its reverse (13413304244031), we get a palindrome (26457544575462).

The spelling of 13044240331431 in words is "thirteen trillion, forty-four billion, two hundred forty million, three hundred thirty-one thousand, four hundred thirty-one".