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1305440400011 = 112063286120107
BaseRepresentation
bin10010111111110010010…
…011111011001010001011
311121210120101102102000212
4102333302103323022023
5132342020220300021
62435413330151335
7163213013213036
oct22776223731213
94553511372025
101305440400011
114636a8089250
1219100542254b
1396144271247
144727dd2a01d
1523e5687085b
hex12ff24fb28b

1305440400011 has 16 divisors (see below), whose sum is σ = 1425376009728. Its totient is φ = 1185715159200.

The previous prime is 1305440399969. The next prime is 1305440400013. The reversal of 1305440400011 is 1100040445031.

It is not a de Polignac number, because 1305440400011 - 218 = 1305440137867 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1305440400011.

It is not an unprimeable number, because it can be changed into a prime (1305440400013) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 64914620 + ... + 64934726.

It is an arithmetic number, because the mean of its divisors is an integer number (89086000608).

Almost surely, 21305440400011 is an apocalyptic number.

1305440400011 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1305440400011 is a deficient number, since it is larger than the sum of its proper divisors (119935609717).

1305440400011 is a wasteful number, since it uses less digits than its factorization.

1305440400011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25042.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 1305440400011 its reverse (1100040445031), we get a palindrome (2405480845042).

The spelling of 1305440400011 in words is "one trillion, three hundred five billion, four hundred forty million, four hundred thousand, eleven".

Divisors: 1 11 2063 2861 20107 22693 31471 221177 5902243 41480741 57526127 64924673 456288151 632787397 118676400001 1305440400011