Base | Representation |
---|---|
bin | 111100110010110010… |
… | …0001110011110001001 |
3 | 110110222110112021102111 |
4 | 1321211210032132021 |
5 | 4114333032423103 |
6 | 135550352102321 |
7 | 12301140211342 |
oct | 1714544163611 |
9 | 413873467374 |
10 | 130553014153 |
11 | 50404855921 |
12 | 21375b349a1 |
13 | c40762bc43 |
14 | 6466b010c9 |
15 | 35e169e86d |
hex | 1e6590e789 |
130553014153 has 2 divisors, whose sum is σ = 130553014154. Its totient is φ = 130553014152.
The previous prime is 130553014147. The next prime is 130553014157. The reversal of 130553014153 is 351410355031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 68378589049 + 62174425104 = 261493^2 + 249348^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130553014153 is a prime.
It is not a weakly prime, because it can be changed into another prime (130553014157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65276507076 + 65276507077.
It is an arithmetic number, because the mean of its divisors is an integer number (65276507077).
Almost surely, 2130553014153 is an apocalyptic number.
It is an amenable number.
130553014153 is a deficient number, since it is larger than the sum of its proper divisors (1).
130553014153 is an equidigital number, since it uses as much as digits as its factorization.
130553014153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 130553014153 its reverse (351410355031), we get a palindrome (481963369184).
The spelling of 130553014153 in words is "one hundred thirty billion, five hundred fifty-three million, fourteen thousand, one hundred fifty-three".
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