Base | Representation |
---|---|
bin | 10011000100000010010… |
… | …001101010011100010000 |
3 | 11122020100101011011122102 |
4 | 103010002101222130100 |
5 | 132430341310210000 |
6 | 2441450203055532 |
7 | 163434046363052 |
oct | 23040221523420 |
9 | 4566311134572 |
10 | 1310003210000 |
11 | 4656297299a1 |
12 | 191a795115a8 |
13 | 966c0669a04 |
14 | 47593d058d2 |
15 | 241222193d5 |
hex | 1310246a710 |
1310003210000 has 50 divisors (see below), whose sum is σ = 3171648795942. Its totient is φ = 524001280000.
The previous prime is 1310003209987. The next prime is 1310003210017. The reversal of 1310003210000 is 123000131.
It can be written as a sum of positive squares in 5 ways, for example, as 279794449936 + 1030208760064 = 528956^2 + 1014992^2 .
It is a tau number, because it is divible by the number of its divisors (50).
It is a super-2 number, since 2×13100032100002 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 65490161 + ... + 65510160.
Almost surely, 21310003210000 is an apocalyptic number.
1310003210000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1310003210000 is an abundant number, since it is smaller than the sum of its proper divisors (1861645585942).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1310003210000 is an equidigital number, since it uses as much as digits as its factorization.
1310003210000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 131000349 (or 131000328 counting only the distinct ones).
The product of its (nonzero) digits is 18, while the sum is 11.
Adding to 1310003210000 its reverse (123000131), we get a palindrome (1310126210131).
The spelling of 1310003210000 in words is "one trillion, three hundred ten billion, three million, two hundred ten thousand".
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