1310003210017 has 2 divisors, whose sum is σ = 1310003210018. Its totient is φ = 1310003210016.

The previous prime is 1310003209987. The next prime is 1310003210023. The reversal of 1310003210017 is 7100123000131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1194541888401 + 115461321616 = 1092951^2 + 339796^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1310003210017 is a prime.

It is a super-2 number, since 2×1310003210017² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1310003209976 and 1310003210003.

It is not a weakly prime, because it can be changed into another prime (1310003210917) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655001605008 + 655001605009.

It is an arithmetic number, because the mean of its divisors is an integer number (655001605009).

Almost surely, 2^{1310003210017} is an apocalyptic number.

It is an amenable number.

1310003210017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310003210017 is an equidigital number, since it uses as much as digits as its factorization.

1310003210017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 126, while the sum is 19.

Adding to 1310003210017 its reverse (7100123000131), we get a palindrome (8410126210148).

The spelling of 1310003210017 in words is "one trillion, three hundred ten billion, three million, two hundred ten thousand, seventeen".