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BaseRepresentation
bin10011000100000010010…
…001101010011101000101
311122020100101011011201101
4103010002101222131011
5132430341310210203
62441450203100101
7163434046363156
oct23040221523505
94566311134641
101310003210053
11465629729a3a
12191a79511631
13966c0669a45
1447593d0592d
152412221941d
hex1310246a745

1310003210053 has 2 divisors, whose sum is σ = 1310003210054. Its totient is φ = 1310003210052.

The previous prime is 1310003210041. The next prime is 1310003210129. The reversal of 1310003210053 is 3500123000131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1305770146209 + 4233063844 = 1142703^2 + 65062^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310003210053 - 217 = 1310003078981 is a prime.

It is a super-2 number, since 2×13100032100532 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1310003210053.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310003210023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655001605026 + 655001605027.

It is an arithmetic number, because the mean of its divisors is an integer number (655001605027).

Almost surely, 21310003210053 is an apocalyptic number.

It is an amenable number.

1310003210053 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310003210053 is an equidigital number, since it uses as much as digits as its factorization.

1310003210053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 270, while the sum is 19.

Adding to 1310003210053 its reverse (3500123000131), we get a palindrome (4810126210184).

The spelling of 1310003210053 in words is "one trillion, three hundred ten billion, three million, two hundred ten thousand, fifty-three".