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BaseRepresentation
bin10011000100000010010…
…001101010011101110111
311122020100101011011210020
4103010002101222131313
5132430341310210403
62441450203100223
7163434046363260
oct23040221523567
94566311134706
101310003210103
11465629729a85
12191a79511673
13966c0669a83
1447593d05967
1524122219453
hex1310246a777

1310003210103 has 16 divisors (see below), whose sum is σ = 2113618625280. Its totient is φ = 704539541376.

The previous prime is 1310003210053. The next prime is 1310003210129. The reversal of 1310003210103 is 3010123000131.

It is not a de Polignac number, because 1310003210103 - 29 = 1310003209591 is a prime.

It is a super-2 number, since 2×13100032101032 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310003210203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1834738033 + ... + 1834738746.

It is an arithmetic number, because the mean of its divisors is an integer number (132101164080).

Almost surely, 21310003210103 is an apocalyptic number.

1310003210103 is a deficient number, since it is larger than the sum of its proper divisors (803615415177).

1310003210103 is a wasteful number, since it uses less digits than its factorization.

1310003210103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3669476806.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 1310003210103 its reverse (3010123000131), we get a palindrome (4320126210234).

The spelling of 1310003210103 in words is "one trillion, three hundred ten billion, three million, two hundred ten thousand, one hundred three".