Base | Representation |
---|---|
bin | 111101000000001000… |
… | …1010001101001001111 |
3 | 110112010200112220100012 |
4 | 1322000101101221033 |
5 | 4121242230444442 |
6 | 140103034423435 |
7 | 12315220251542 |
oct | 1720021215117 |
9 | 415120486305 |
10 | 131001031247 |
11 | 50614737789 |
12 | 2147bb91b7b |
13 | c4793b3208 |
14 | 64aa404859 |
15 | 361ab9a582 |
hex | 1e80451a4f |
131001031247 has 2 divisors, whose sum is σ = 131001031248. Its totient is φ = 131001031246.
The previous prime is 131001031181. The next prime is 131001031267. The reversal of 131001031247 is 742130100131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131001031247 - 212 = 131001027151 is a prime.
It is a super-2 number, since 2×1310010312472 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131001031267) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500515623 + 65500515624.
It is an arithmetic number, because the mean of its divisors is an integer number (65500515624).
Almost surely, 2131001031247 is an apocalyptic number.
131001031247 is a deficient number, since it is larger than the sum of its proper divisors (1).
131001031247 is an equidigital number, since it uses as much as digits as its factorization.
131001031247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 131001031247 its reverse (742130100131), we get a palindrome (873131131378).
The spelling of 131001031247 in words is "one hundred thirty-one billion, one million, thirty-one thousand, two hundred forty-seven".
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