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131002131024221 is a prime number
BaseRepresentation
bin11101110010010101001111…
…011111000000100101011101
3122011211200101202022221220212
4131302111033133000211131
5114132314331020233341
61142341314223422205
736410406633650222
oct3562251737004535
9564750352287825
10131002131024221
1138817767821166
1212839110754965
1358135a91b1ab2
14244c773649949
1510229ece545eb
hex77254f7c095d

131002131024221 has 2 divisors, whose sum is σ = 131002131024222. Its totient is φ = 131002131024220.

The previous prime is 131002131024217. The next prime is 131002131024241. The reversal of 131002131024221 is 122420131200131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 126301859328100 + 4700271696121 = 11238410^2 + 2168011^2 .

It is a cyclic number.

It is not a de Polignac number, because 131002131024221 - 22 = 131002131024217 is a prime.

It is a super-3 number, since 3×1310021310242213 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131002131024241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65501065512110 + 65501065512111.

It is an arithmetic number, because the mean of its divisors is an integer number (65501065512111).

Almost surely, 2131002131024221 is an apocalyptic number.

It is an amenable number.

131002131024221 is a deficient number, since it is larger than the sum of its proper divisors (1).

131002131024221 is an equidigital number, since it uses as much as digits as its factorization.

131002131024221 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 131002131024221 its reverse (122420131200131), we get a palindrome (253422262224352).

The spelling of 131002131024221 in words is "one hundred thirty-one trillion, two billion, one hundred thirty-one million, twenty-four thousand, two hundred twenty-one".