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13101034341000 = 23353311134912539
BaseRepresentation
bin1011111010100101001001…
…1111111000001010001000
31201101110001121102211122010
42332221102133320022020
53204121404242403000
643510310533055520
72521342562336334
oct276512237701210
951343047384563
1013101034341000
1141a1132384571
121577099a875a0
13740564869b48
143341445b27c4
1517abc45d7d50
hexbea527f8288

13101034341000 has 512 divisors, whose sum is σ = 42670673510400. Its totient is φ = 3342850560000.

The previous prime is 13101034340987. The next prime is 13101034341001. The reversal of 13101034341000 is 14343010131.

13101034341000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×131010343410002 (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13101034341001) by changing a digit.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 5159917731 + ... + 5159920269.

It is an arithmetic number, because the mean of its divisors is an integer number (83341159200).

Almost surely, 213101034341000 is an apocalyptic number.

13101034341000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13101034341000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21335336755200).

13101034341000 is an abundant number, since it is smaller than the sum of its proper divisors (29569639169400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13101034341000 is a wasteful number, since it uses less digits than its factorization.

13101034341000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3198 (or 3184 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 13101034341000 its reverse (14343010131), we get a palindrome (13115377351131).

The spelling of 13101034341000 in words is "thirteen trillion, one hundred one billion, thirty-four million, three hundred forty-one thousand".