131012143414033 has 4 divisors (see below), whose sum is σ = 149728163901760. Its totient is φ = 112296122926308.

The previous prime is 131012143414001. The next prime is 131012143414049. The reversal of 131012143414033 is 330414341210131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131012143414033 - 2⁵ = 131012143414001 is a prime.

It is a super-2 number, since 2×131012143414033² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131012143413986 and 131012143414004.

It is not an unprimeable number, because it can be changed into a prime (131012143414063) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9358010243853 + ... + 9358010243866.

It is an arithmetic number, because the mean of its divisors is an integer number (37432040975440).

Almost surely, 2^{131012143414033} is an apocalyptic number.

It is an amenable number.

131012143414033 is a deficient number, since it is larger than the sum of its proper divisors (18716020487727).

131012143414033 is an equidigital number, since it uses as much as digits as its factorization.

131012143414033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18716020487726.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 131012143414033 its reverse (330414341210131), we get a palindrome (461426484624164).

The spelling of 131012143414033 in words is "one hundred thirty-one trillion, twelve billion, one hundred forty-three million, four hundred fourteen thousand, thirty-three".