Base | Representation |
---|---|
bin | 11101110010011110101000… |
… | …111010101111100001110011 |
3 | 122011212122102222011012221212 |
4 | 131302132220322233201303 |
5 | 114133001012134314303 |
6 | 1142350103355310335 |
7 | 36411214656515012 |
oct | 3562365072574163 |
9 | 564778388135855 |
10 | 131012221401203 |
11 | 38820a7555479a |
12 | 1283b067a4b3ab |
13 | 581452682396c |
14 | 244d04d7b6a79 |
15 | 1022dddc15ad8 |
hex | 7727a8eaf873 |
131012221401203 has 2 divisors, whose sum is σ = 131012221401204. Its totient is φ = 131012221401202.
The previous prime is 131012221401179. The next prime is 131012221401239. The reversal of 131012221401203 is 302104122210131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131012221401203 - 212 = 131012221397107 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (131012221001203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506110700601 + 65506110700602.
It is an arithmetic number, because the mean of its divisors is an integer number (65506110700602).
Almost surely, 2131012221401203 is an apocalyptic number.
131012221401203 is a deficient number, since it is larger than the sum of its proper divisors (1).
131012221401203 is an equidigital number, since it uses as much as digits as its factorization.
131012221401203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 131012221401203 its reverse (302104122210131), we get a palindrome (433116343611334).
The spelling of 131012221401203 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-one million, four hundred one thousand, two hundred three".
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