Base | Representation |
---|---|
bin | 11101110010011110101001… |
… | …000100110011110010110000 |
3 | 122011212122110011010021212020 |
4 | 131302132221010303302300 |
5 | 114133001013323240422 |
6 | 1142350103532031440 |
7 | 36411215021115432 |
oct | 3562365104636260 |
9 | 564778404107766 |
10 | 131012224040112 |
11 | 38820a76a97408 |
12 | 1283b068902580 |
13 | 5814527238b4c |
14 | 244d04dca2652 |
15 | 1022dde08795c |
hex | 7727a9133cb0 |
131012224040112 has 20 divisors (see below), whose sum is σ = 338448245437080. Its totient is φ = 43670741346688.
The previous prime is 131012224040107. The next prime is 131012224040129. The reversal of 131012224040112 is 211040422210131.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1364710667037 + ... + 1364710667132.
It is an arithmetic number, because the mean of its divisors is an integer number (16922412271854).
Almost surely, 2131012224040112 is an apocalyptic number.
131012224040112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
131012224040112 is an abundant number, since it is smaller than the sum of its proper divisors (207436021396968).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131012224040112 is a wasteful number, since it uses less digits than its factorization.
131012224040112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2729421334180 (or 2729421334174 counting only the distinct ones).
The product of its (nonzero) digits is 768, while the sum is 24.
Adding to 131012224040112 its reverse (211040422210131), we get a palindrome (342052646250243).
The spelling of 131012224040112 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-four million, forty thousand, one hundred twelve".
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