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131012224204373 is a prime number
BaseRepresentation
bin11101110010011110101001…
…000101011011111001010101
3122011212122110011102122011222
4131302132221011123321111
5114133001013344014443
61142350103535340125
736411215022401351
oct3562365105337125
9564778404378158
10131012224204373
1138820a77099866
121283b068981645
135814527295845
14244d04dd06461
151022dde0bb468
hex7727a915be55

131012224204373 has 2 divisors, whose sum is σ = 131012224204374. Its totient is φ = 131012224204372.

The previous prime is 131012224204331. The next prime is 131012224204417. The reversal of 131012224204373 is 373402422210131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 82965464497444 + 48046759706929 = 9108538^2 + 6931577^2 .

It is a cyclic number.

It is not a de Polignac number, because 131012224204373 - 28 = 131012224204117 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131012224204573) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506112102186 + 65506112102187.

It is an arithmetic number, because the mean of its divisors is an integer number (65506112102187).

Almost surely, 2131012224204373 is an apocalyptic number.

It is an amenable number.

131012224204373 is a deficient number, since it is larger than the sum of its proper divisors (1).

131012224204373 is an equidigital number, since it uses as much as digits as its factorization.

131012224204373 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48384, while the sum is 35.

The spelling of 131012224204373 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-four million, two hundred four thousand, three hundred seventy-three".