13101313001112 has 160 divisors (see below), whose sum is σ = 41988666218400. Its totient is φ = 3738715854336.

The previous prime is 13101313001111. The next prime is 13101313001113. The reversal of 13101313001112 is 21110031310131.

13101313001112 is a `hidden beast` number, since 1 + 310 + 1 + 31 + 300 + 11 + 12 = 666.

13101313001112 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (13101313001111) and next prime (13101313001113).

It is a super-2 number, since 2×13101313001112² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13101313001111) by changing a digit.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 2018308 + ... + 5502380.

It is an arithmetic number, because the mean of its divisors is an integer number (262429163865).

Almost surely, 2^{13101313001112} is an apocalyptic number.

13101313001112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13101313001112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20994333109200).

13101313001112 is an abundant number, since it is smaller than the sum of its proper divisors (28887353217288).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13101313001112 is a wasteful number, since it uses less digits than its factorization.

13101313001112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3484927 (or 3484914 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 13101313001112 its reverse (21110031310131), we get a palindrome (34211344311243).

The spelling of 13101313001112 in words is "thirteen trillion, one hundred one billion, three hundred thirteen million, one thousand, one hundred twelve".