Base | Representation |
---|---|
bin | 1011111010110001011100… |
… | …1011111000001111111101 |
3 | 1201101202120120201112222011 |
4 | 2332230113023320033331 |
5 | 3204200134024210140 |
6 | 43512014212451221 |
7 | 2521520421634651 |
oct | 276542713701775 |
9 | 51352516645864 |
10 | 13104334210045 |
11 | 41a2576039a71 |
12 | 157785b019b11 |
13 | 74096c404690 |
14 | 334378956a61 |
15 | 17ad19161cea |
hex | beb172f83fd |
13104334210045 has 16 divisors (see below), whose sum is σ = 16957935418032. Its totient is φ = 9663844792320.
The previous prime is 13104334210007. The next prime is 13104334210109. The reversal of 13104334210045 is 54001243340131.
It can be written as a sum of positive squares in 8 ways, for example, as 1913723623876 + 11190610586169 = 1383374^2 + 3345237^2 .
It is not a de Polignac number, because 13104334210045 - 213 = 13104334201853 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13104334209989 and 13104334210016.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 137472916 + ... + 137568205.
It is an arithmetic number, because the mean of its divisors is an integer number (1059870963627).
Almost surely, 213104334210045 is an apocalyptic number.
It is an amenable number.
13104334210045 is a deficient number, since it is larger than the sum of its proper divisors (3853601207987).
13104334210045 is a wasteful number, since it uses less digits than its factorization.
13104334210045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 275041872.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 13104334210045 its reverse (54001243340131), we get a palindrome (67105577550176).
The spelling of 13104334210045 in words is "thirteen trillion, one hundred four billion, three hundred thirty-four million, two hundred ten thousand, forty-five".
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