Base | Representation |
---|---|
bin | 111101000001110010… |
… | …0101100001110010111 |
3 | 110112021112211121000022 |
4 | 1322003210230032113 |
5 | 4121400422440003 |
6 | 140112334335355 |
7 | 12316462315544 |
oct | 1720344541627 |
9 | 415245747008 |
10 | 131056452503 |
11 | 50642a50579 |
12 | 2149665a55b |
13 | c487a19062 |
14 | 64b390dbcb |
15 | 3620996738 |
hex | 1e8392c397 |
131056452503 has 4 divisors (see below), whose sum is σ = 131359123728. Its totient is φ = 130753781280.
The previous prime is 131056452497. The next prime is 131056452533. The reversal of 131056452503 is 305254650131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131056452503 - 24 = 131056452487 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131056452533) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 151334963 + ... + 151335828.
It is an arithmetic number, because the mean of its divisors is an integer number (32839780932).
Almost surely, 2131056452503 is an apocalyptic number.
131056452503 is a deficient number, since it is larger than the sum of its proper divisors (302671225).
131056452503 is an equidigital number, since it uses as much as digits as its factorization.
131056452503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 302671224.
The product of its (nonzero) digits is 54000, while the sum is 35.
The spelling of 131056452503 in words is "one hundred thirty-one billion, fifty-six million, four hundred fifty-two thousand, five hundred three".
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