Base | Representation |
---|---|
bin | 1011111011000110111110… |
… | …0100110010010001010101 |
3 | 1201102022111020211211221112 |
4 | 2332301233210302101111 |
5 | 3204244002144221321 |
6 | 43514411413024405 |
7 | 2522113541125304 |
oct | 276615744622125 |
9 | 51368436754845 |
10 | 13110112101461 |
11 | 41a4a70557341 |
12 | 15789b2025105 |
13 | 74138047503b |
14 | 33476606a43b |
15 | 17b056524a5b |
hex | bec6f932455 |
13110112101461 has 2 divisors, whose sum is σ = 13110112101462. Its totient is φ = 13110112101460.
The previous prime is 13110112101439. The next prime is 13110112101529. The reversal of 13110112101461 is 16410121101131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11367646100836 + 1742466000625 = 3371594^2 + 1320025^2 .
It is a cyclic number.
It is not a de Polignac number, because 13110112101461 - 26 = 13110112101397 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13110112101761) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555056050730 + 6555056050731.
It is an arithmetic number, because the mean of its divisors is an integer number (6555056050731).
Almost surely, 213110112101461 is an apocalyptic number.
It is an amenable number.
13110112101461 is a deficient number, since it is larger than the sum of its proper divisors (1).
13110112101461 is an equidigital number, since it uses as much as digits as its factorization.
13110112101461 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 23.
Adding to 13110112101461 its reverse (16410121101131), we get a palindrome (29520233202592).
The spelling of 13110112101461 in words is "thirteen trillion, one hundred ten billion, one hundred twelve million, one hundred one thousand, four hundred sixty-one".
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