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131102223121 = 439129857031
BaseRepresentation
bin111101000011001001…
…1010010101100010001
3110112101201221222111101
41322012103102230101
54121444132114441
6140121051344401
712320556336562
oct1720623225421
9415351858441
10131102223121
1150666872731
12214a9a52101
13c49435336c
1464b9a26169
1536249d8231
hex1e864d2b11

131102223121 has 4 divisors (see below), whose sum is σ = 131132084544. Its totient is φ = 131072361700.

The previous prime is 131102223089. The next prime is 131102223181. The reversal of 131102223121 is 121322201131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131102223121 - 25 = 131102223089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131102223181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14924125 + ... + 14932906.

It is an arithmetic number, because the mean of its divisors is an integer number (32783021136).

Almost surely, 2131102223121 is an apocalyptic number.

It is an amenable number.

131102223121 is a deficient number, since it is larger than the sum of its proper divisors (29861423).

131102223121 is an equidigital number, since it uses as much as digits as its factorization.

131102223121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29861422.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 131102223121 its reverse (121322201131), we get a palindrome (252424424252).

The spelling of 131102223121 in words is "one hundred thirty-one billion, one hundred two million, two hundred twenty-three thousand, one hundred twenty-one".

Divisors: 1 4391 29857031 131102223121