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13110231311 = 23570010057
BaseRepresentation
bin11000011010110111…
…00100000100001111
31020211200012202101122
430031123210010033
5203322204400221
610004525431155
7642612061502
oct141533440417
936750182348
1013110231311
115618424911
12265a70b4bb
13130c188428
148c5261139
1551ae77eab
hex30d6e410f

13110231311 has 4 divisors (see below), whose sum is σ = 13680241392. Its totient is φ = 12540221232.

The previous prime is 13110231301. The next prime is 13110231313. The reversal of 13110231311 is 11313201131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11313201131 = 71159340861.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13110231311 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13110231311.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13110231313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 285005006 + ... + 285005051.

It is an arithmetic number, because the mean of its divisors is an integer number (3420060348).

Almost surely, 213110231311 is an apocalyptic number.

13110231311 is a deficient number, since it is larger than the sum of its proper divisors (570010081).

13110231311 is an equidigital number, since it uses as much as digits as its factorization.

13110231311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 570010080.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 13110231311 its reverse (11313201131), we get a palindrome (24423432442).

The spelling of 13110231311 in words is "thirteen billion, one hundred ten million, two hundred thirty-one thousand, three hundred eleven".

Divisors: 1 23 570010057 13110231311