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13110257 is a prime number
BaseRepresentation
bin110010000000…
…101111110001
3220200001220002
4302000233301
511324012012
61144555345
7216302216
oct62005761
926601802
1013110257
117444a26
124482b55
132940464
141a53b0d
15123e7c2
hexc80bf1

13110257 has 2 divisors, whose sum is σ = 13110258. Its totient is φ = 13110256.

The previous prime is 13110187. The next prime is 13110259. The reversal of 13110257 is 75201131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8620096 + 4490161 = 2936^2 + 2119^2 .

It is a cyclic number.

It is not a de Polignac number, because 13110257 - 218 = 12848113 is a prime.

Together with 13110259, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13110259) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555128 + 6555129.

It is an arithmetic number, because the mean of its divisors is an integer number (6555129).

Almost surely, 213110257 is an apocalyptic number.

It is an amenable number.

13110257 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110257 is an equidigital number, since it uses as much as digits as its factorization.

13110257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 210, while the sum is 20.

The square root of 13110257 is about 3620.8088875278. The cubic root of 13110257 is about 235.7963447034.

Adding to 13110257 its reverse (75201131), we get a palindrome (88311388).

It can be divided in two parts, 13 and 110257, that multiplied together give a palindrome (1433341).

The spelling of 13110257 in words is "thirteen million, one hundred ten thousand, two hundred fifty-seven".