Base | Representation |
---|---|
bin | 11000011010111001… |
… | …01111101110111101 |
3 | 1020211200210111112200 |
4 | 30031130233232331 |
5 | 203322244304440 |
6 | 10004540222113 |
7 | 642614522214 |
oct | 141534575675 |
9 | 36750714480 |
10 | 13110541245 |
11 | 561861675a |
12 | 265a83a939 |
13 | 130c266519 |
14 | 8c530207b |
15 | 51aed9c30 |
hex | 30d72fbbd |
13110541245 has 24 divisors (see below), whose sum is σ = 22861028736. Its totient is φ = 6950414688.
The previous prime is 13110541231. The next prime is 13110541247. The reversal of 13110541245 is 54214501131.
13110541245 is a `hidden beast` number, since 1 + 3 + 110 + 541 + 2 + 4 + 5 = 666.
It is not a de Polignac number, because 13110541245 - 29 = 13110540733 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13110541247) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 864777 + ... + 879806.
It is an arithmetic number, because the mean of its divisors is an integer number (952542864).
Almost surely, 213110541245 is an apocalyptic number.
13110541245 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13110541245 is a deficient number, since it is larger than the sum of its proper divisors (9750487491).
13110541245 is a wasteful number, since it uses less digits than its factorization.
13110541245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1744761 (or 1744758 counting only the distinct ones).
The product of its (nonzero) digits is 2400, while the sum is 27.
The spelling of 13110541245 in words is "thirteen billion, one hundred ten million, five hundred forty-one thousand, two hundred forty-five".
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