Base | Representation |
---|---|
bin | 111101000011011000… |
… | …1010110000010110101 |
3 | 110112102021210020011002 |
4 | 1322012301112002311 |
5 | 4122003141214143 |
6 | 140121532253045 |
7 | 12321013320632 |
oct | 1720661260265 |
9 | 415367706132 |
10 | 131110101173 |
11 | 50670263617 |
12 | 214b0611185 |
13 | c495b8112c |
14 | 64baab7189 |
15 | 36255425b8 |
hex | 1e86c560b5 |
131110101173 has 2 divisors, whose sum is σ = 131110101174. Its totient is φ = 131110101172.
The previous prime is 131110101151. The next prime is 131110101191. The reversal of 131110101173 is 371101011131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 115670050609 + 15440050564 = 340103^2 + 124258^2 .
It is a cyclic number.
It is not a de Polignac number, because 131110101173 - 212 = 131110097077 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131110101373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65555050586 + 65555050587.
It is an arithmetic number, because the mean of its divisors is an integer number (65555050587).
Almost surely, 2131110101173 is an apocalyptic number.
It is an amenable number.
131110101173 is a deficient number, since it is larger than the sum of its proper divisors (1).
131110101173 is an equidigital number, since it uses as much as digits as its factorization.
131110101173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 63, while the sum is 20.
The spelling of 131110101173 in words is "one hundred thirty-one billion, one hundred ten million, one hundred one thousand, one hundred seventy-three".
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