13111310450137 has 4 divisors (see below), whose sum is σ = 13563424603620. Its totient is φ = 12659196296656.

The previous prime is 13111310450107. The next prime is 13111310450153. The reversal of 13111310450137 is 73105401311131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3747337126416 + 9363973323721 = 1935804^2 + 3060061^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13111310450137 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13111310450099 and 13111310450108.

It is not an unprimeable number, because it can be changed into a prime (13111310450107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 226057076698 + ... + 226057076755.

It is an arithmetic number, because the mean of its divisors is an integer number (3390856150905).

Almost surely, 2^{13111310450137} is an apocalyptic number.

It is an amenable number.

13111310450137 is a deficient number, since it is larger than the sum of its proper divisors (452114153483).

13111310450137 is an equidigital number, since it uses as much as digits as its factorization.

13111310450137 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 452114153482.

The product of its (nonzero) digits is 3780, while the sum is 31.

Adding to 13111310450137 its reverse (73105401311131), we get a palindrome (86216711761268).

The spelling of 13111310450137 in words is "thirteen trillion, one hundred eleven billion, three hundred ten million, four hundred fifty thousand, one hundred thirty-seven".